P^-3/4-5P^-19/4

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Solution for P^-3/4-5P^-19/4 equation: 


D( P )

P = 0

P = 0

P = 0

P in (-oo:0) U (0:+oo)

(P^-3)/4-((5*P^-19)/4) = 0

(P^-3)/4+(-5/4)*P^-19 = 0

1/4*P^-3-5/4*P^-19 = 0

1/4*P^-3*(1-5*P^-16) = 0

-5*P^-16 = -1 // : -5

P^-16 = 1/5

-16 < 0

1/(P^16) = 1/5 // * P^16

1 = 1/5*P^16 // : 1/5

5 = P^16

P^16 = 5 // ^ 1/16

abs(P) = 5^(1/16)

P = 5^(1/16) or P = -5^(1/16)

1/(4*P^3) = 0

1/4*P^-3 = 0 // : 1/4

P^-3 = 0

P naleu017Cy do O

P in { 5^(1/16), -5^(1/16) }

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